{\left(1 + x\right)}^{y}{\left(1 + x\right)}^{y}double code(double x, double y) {
return ((double) pow(((double) (1.0 + x)), y));
}
double code(double x, double y) {
return ((double) pow(((double) (1.0 + x)), y));
}



Bits error versus x



Bits error versus y
Results
Initial program 5.7
Final simplification5.7
herbie shell --seed 2020153
(FPCore (x y)
:name "(pow (+ 1 x) y)"
:precision binary64
(pow (+ 1.0 x) y))