Average Error: 0 → 0
Time: 1.1s
Precision: binary64
\[{n}^{n}\]
↓
\[{n}^{n}\]
{n}^{n}
↓
{n}^{n}
double code(double n) {
	return ((double) pow(n, n));
}
↓
double code(double n) {
	return ((double) pow(n, n));
}

Error

Bits error versus n

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0

    \[{n}^{n}\]

  2. Final simplification0

    \[\leadsto {n}^{n}\]

Reproduce

herbie shell --seed 2020153 
(FPCore (n)
  :name "(pow n n)"
  :precision binary64
  (pow n n))