Average Error: 0.0 → 0.0
Time: 404.0ms
Precision: binary64
\[x \cdot 0.10000000000000001 + 100\]
↓
\[x \cdot 0.10000000000000001 + 100\]
x \cdot 0.10000000000000001 + 100
↓
x \cdot 0.10000000000000001 + 100
double code(double x) {
	return ((double) (((double) (x * 0.1)) + 100.0));
}
↓
double code(double x) {
	return ((double) (((double) (x * 0.1)) + 100.0));
}

Error

Bits error versus x

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.0

    \[x \cdot 0.10000000000000001 + 100\]

  2. Final simplification0.0

    \[\leadsto x \cdot 0.10000000000000001 + 100\]

Reproduce

herbie shell --seed 2020153 
(FPCore (x)
  :name "(+ (* x 0.1) 100)"
  :precision binary64
  (+ (* x 0.1) 100.0))