Average Error: 6.2 → 6.2
Time: 3.1s
Precision: binary64
\[\frac{1}{{\left(1 + x\right)}^{n}}\]
↓
\[\frac{1}{{\left(1 + x\right)}^{n}}\]
\frac{1}{{\left(1 + x\right)}^{n}}
↓
\frac{1}{{\left(1 + x\right)}^{n}}
double code(double x, double n) {
	return ((double) (1.0 / ((double) pow(((double) (1.0 + x)), n))));
}
↓
double code(double x, double n) {
	return ((double) (1.0 / ((double) pow(((double) (1.0 + x)), n))));
}

Error

Bits error versus x

Bits error versus n

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 6.2

    \[\frac{1}{{\left(1 + x\right)}^{n}}\]

  2. Final simplification6.2

    \[\leadsto \frac{1}{{\left(1 + x\right)}^{n}}\]

Reproduce

herbie shell --seed 2020153 
(FPCore (x n)
  :name "(/ 1 (pow (+ 1 x) n))"
  :precision binary64
  (/ 1.0 (pow (+ 1.0 x) n)))