{\left(x + 1\right)}^{n}{\left(x + 1\right)}^{n}double code(double x, double n) {
return ((double) pow(((double) (x + 1.0)), n));
}
double code(double x, double n) {
return ((double) pow(((double) (x + 1.0)), n));
}



Bits error versus x



Bits error versus n
Results
Initial program 5.6
Final simplification5.6
herbie shell --seed 2020152
(FPCore (x n)
:name "(pow (+ x 1) n)"
:precision binary64
(pow (+ x 1.0) n))