Average Error: 0.0 → 0.0
Time: 1.5s
Precision: binary64
\[{\left(\frac{1}{x}\right)}^{n}\]
↓
\[{\left(\frac{1}{x}\right)}^{n}\]
{\left(\frac{1}{x}\right)}^{n}
↓
{\left(\frac{1}{x}\right)}^{n}
double code(double x, double n) {
	return ((double) pow(((double) (1.0 / x)), n));
}
↓
double code(double x, double n) {
	return ((double) pow(((double) (1.0 / x)), n));
}

Error

Bits error versus x

Bits error versus n

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.0

    \[{\left(\frac{1}{x}\right)}^{n}\]

  2. Final simplification0.0

    \[\leadsto {\left(\frac{1}{x}\right)}^{n}\]

Reproduce

herbie shell --seed 2020152 
(FPCore (x n)
  :name "(pow (/ 1 x) n)"
  :precision binary64
  (pow (/ 1.0 x) n))