Average Error: 0.1 → 0.1
Time: 730.0ms
Precision: binary64
\[\frac{\log \left(2 + x\right)}{1 + x}\]
↓
\[\frac{\log \left(2 + x\right)}{1 + x}\]
\frac{\log \left(2 + x\right)}{1 + x}
↓
\frac{\log \left(2 + x\right)}{1 + x}
double code(double x) {
	return ((double) (((double) log(((double) (2.0 + x)))) / ((double) (1.0 + x))));
}
↓
double code(double x) {
	return ((double) (((double) log(((double) (2.0 + x)))) / ((double) (1.0 + x))));
}

Error

Bits error versus x

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.1

    \[\frac{\log \left(2 + x\right)}{1 + x}\]

  2. Final simplification0.1

    \[\leadsto \frac{\log \left(2 + x\right)}{1 + x}\]

Reproduce

herbie shell --seed 2020152 
(FPCore (x)
  :name "(/ (log (+ 2 x)) (+ 1 x))"
  :precision binary64
  (/ (log (+ 2.0 x)) (+ 1.0 x)))