Average Error: 7.4 → 0.6
Time: 3.5s
Precision: binary64
\[\frac{\cosh x \cdot \frac{y}{x}}{z}\]
↓
\[\begin{array}{l} \mathbf{if}\;z \le -8.06565750284886438 \cdot 10^{27} \lor \neg \left(z \le 2.0317376429161032 \cdot 10^{38}\right):\\ \;\;\;\;\left(\cosh x \cdot y\right) \cdot \frac{1}{z \cdot x}\\ \mathbf{else}:\\ \;\;\;\;\frac{\cosh x}{\frac{z}{\frac{y}{x}}}\\ \end{array}\]
\frac{\cosh x \cdot \frac{y}{x}}{z}
↓
\begin{array}{l}
\mathbf{if}\;z \le -8.06565750284886438 \cdot 10^{27} \lor \neg \left(z \le 2.0317376429161032 \cdot 10^{38}\right):\\
\;\;\;\;\left(\cosh x \cdot y\right) \cdot \frac{1}{z \cdot x}\\

\mathbf{else}:\\
\;\;\;\;\frac{\cosh x}{\frac{z}{\frac{y}{x}}}\\

\end{array}
double code(double x, double y, double z) {
	return ((double) (((double) (((double) cosh(x)) * ((double) (y / x)))) / z));
}
↓
double code(double x, double y, double z) {
	double VAR;
	if (((z <= -8.065657502848864e+27) || !(z <= 2.0317376429161032e+38))) {
		VAR = ((double) (((double) (((double) cosh(x)) * y)) * ((double) (1.0 / ((double) (z * x))))));
	} else {
		VAR = ((double) (((double) cosh(x)) / ((double) (z / ((double) (y / x))))));
	}
	return VAR;
}

Error

Bits error versus x

Bits error versus y

Bits error versus z

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original7.4
Target0.5
Herbie0.6
\[\begin{array}{l} \mathbf{if}\;y \lt -4.618902267687042 \cdot 10^{-52}:\\ \;\;\;\;\frac{\frac{y}{z}}{x} \cdot \cosh x\\ \mathbf{elif}\;y \lt 1.0385305359351529 \cdot 10^{-39}:\\ \;\;\;\;\frac{\frac{\cosh x \cdot y}{x}}{z}\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{y}{z}}{x} \cdot \cosh x\\ \end{array}\]

Derivation

  1. Split input into 2 regimes

  2. if z < -8.06565750284886438e27 or 2.0317376429161032e38 < z

    1. Initial program 12.0

      \[\frac{\cosh x \cdot \frac{y}{x}}{z}\]
    2. Using strategy rm

    3. Applied associate-*r/12.0

      \[\leadsto \frac{\color{blue}{\frac{\cosh x \cdot y}{x}}}{z}\]

    4. Applied associate-/l/0.4

      \[\leadsto \color{blue}{\frac{\cosh x \cdot y}{z \cdot x}}\]
    5. Using strategy rm

    6. Applied div-inv0.5

      \[\leadsto \color{blue}{\left(\cosh x \cdot y\right) \cdot \frac{1}{z \cdot x}}\]

    if -8.06565750284886438e27 < z < 2.0317376429161032e38

    1. Initial program 0.6

      \[\frac{\cosh x \cdot \frac{y}{x}}{z}\]
    2. Using strategy rm

    3. Applied associate-/l*0.7

      \[\leadsto \color{blue}{\frac{\cosh x}{\frac{z}{\frac{y}{x}}}}\]
  3. Recombined 2 regimes into one program.

  4. Final simplification0.6

    \[\leadsto \begin{array}{l} \mathbf{if}\;z \le -8.06565750284886438 \cdot 10^{27} \lor \neg \left(z \le 2.0317376429161032 \cdot 10^{38}\right):\\ \;\;\;\;\left(\cosh x \cdot y\right) \cdot \frac{1}{z \cdot x}\\ \mathbf{else}:\\ \;\;\;\;\frac{\cosh x}{\frac{z}{\frac{y}{x}}}\\ \end{array}\]

Reproduce

herbie shell --seed 2020149 
(FPCore (x y z)
  :name "Linear.Quaternion:$ctan from linear-1.19.1.3"
  :precision binary64

  :herbie-target
  (if (< y -4.618902267687042e-52) (* (/ (/ y z) x) (cosh x)) (if (< y 1.0385305359351529e-39) (/ (/ (* (cosh x) y) x) z) (* (/ (/ y z) x) (cosh x))))

  (/ (* (cosh x) (/ y x)) z))