Average Error: 0.0 → 0.0
Time: 894.0ms
Precision: 64
\[e^{\left(x \cdot y\right) \cdot y}\]
\[e^{\left(x \cdot y\right) \cdot y}\]
e^{\left(x \cdot y\right) \cdot y}
e^{\left(x \cdot y\right) \cdot y}
double f(double x, double y) {
        double r206038 = x;
        double r206039 = y;
        double r206040 = r206038 * r206039;
        double r206041 = r206040 * r206039;
        double r206042 = exp(r206041);
        return r206042;
}

double f(double x, double y) {
        double r206043 = x;
        double r206044 = y;
        double r206045 = r206043 * r206044;
        double r206046 = r206045 * r206044;
        double r206047 = exp(r206046);
        return r206047;
}

Error

Bits error versus x

Bits error versus y

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.0

    \[e^{\left(x \cdot y\right) \cdot y}\]
  2. Final simplification0.0

    \[\leadsto e^{\left(x \cdot y\right) \cdot y}\]

Reproduce

herbie shell --seed 2020100 +o rules:numerics
(FPCore (x y)
  :name "Data.Random.Distribution.Normal:normalF from random-fu-0.2.6.2"
  :precision binary64
  (exp (* (* x y) y)))