\left(\left(x \cdot y + \frac{z \cdot t}{16}\right) - \frac{a \cdot b}{4}\right) + c\mathsf{fma}\left(z, \frac{t}{16}, \mathsf{fma}\left(y, x, \mathsf{fma}\left(-\frac{a}{4}, b, c\right)\right)\right)double f(double x, double y, double z, double t, double a, double b, double c) {
double r254743 = x;
double r254744 = y;
double r254745 = r254743 * r254744;
double r254746 = z;
double r254747 = t;
double r254748 = r254746 * r254747;
double r254749 = 16.0;
double r254750 = r254748 / r254749;
double r254751 = r254745 + r254750;
double r254752 = a;
double r254753 = b;
double r254754 = r254752 * r254753;
double r254755 = 4.0;
double r254756 = r254754 / r254755;
double r254757 = r254751 - r254756;
double r254758 = c;
double r254759 = r254757 + r254758;
return r254759;
}
double f(double x, double y, double z, double t, double a, double b, double c) {
double r254760 = z;
double r254761 = t;
double r254762 = 16.0;
double r254763 = r254761 / r254762;
double r254764 = y;
double r254765 = x;
double r254766 = a;
double r254767 = 4.0;
double r254768 = r254766 / r254767;
double r254769 = -r254768;
double r254770 = b;
double r254771 = c;
double r254772 = fma(r254769, r254770, r254771);
double r254773 = fma(r254764, r254765, r254772);
double r254774 = fma(r254760, r254763, r254773);
return r254774;
}



Bits error versus x



Bits error versus y



Bits error versus z



Bits error versus t



Bits error versus a



Bits error versus b



Bits error versus c
Initial program 0.2
Simplified0.0
Final simplification0.0
herbie shell --seed 2020100 +o rules:numerics
(FPCore (x y z t a b c)
:name "Diagrams.Solve.Polynomial:quartForm from diagrams-solve-0.1, C"
:precision binary64
(+ (- (+ (* x y) (/ (* z t) 16)) (/ (* a b) 4)) c))