Average Error: 0.0 → 0.0
Time: 875.0ms
Precision: 64
\[e^{\left(x \cdot y\right) \cdot y}\]
\[e^{\left(x \cdot y\right) \cdot y}\]
e^{\left(x \cdot y\right) \cdot y}
e^{\left(x \cdot y\right) \cdot y}
double f(double x, double y) {
        double r214833 = x;
        double r214834 = y;
        double r214835 = r214833 * r214834;
        double r214836 = r214835 * r214834;
        double r214837 = exp(r214836);
        return r214837;
}

double f(double x, double y) {
        double r214838 = x;
        double r214839 = y;
        double r214840 = r214838 * r214839;
        double r214841 = r214840 * r214839;
        double r214842 = exp(r214841);
        return r214842;
}

Error

Bits error versus x

Bits error versus y

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.0

    \[e^{\left(x \cdot y\right) \cdot y}\]
  2. Final simplification0.0

    \[\leadsto e^{\left(x \cdot y\right) \cdot y}\]

Reproduce

herbie shell --seed 2020089 +o rules:numerics
(FPCore (x y)
  :name "Data.Random.Distribution.Normal:normalF from random-fu-0.2.6.2"
  :precision binary64
  (exp (* (* x y) y)))