Average Error: 0.8 → 0.8
Time: 3.1s
Precision: 64
\[\frac{\tan^{-1}_* \frac{im}{re}}{\log 10}\]
↓
\[\frac{\tan^{-1}_* \frac{im}{re}}{\log 10}\]
\frac{\tan^{-1}_* \frac{im}{re}}{\log 10}
↓
\frac{\tan^{-1}_* \frac{im}{re}}{\log 10}
double f(double re, double im) {
        double r89325 = im;
        double r89326 = re;
        double r89327 = atan2(r89325, r89326);
        double r89328 = 10.0;
        double r89329 = log(r89328);
        double r89330 = r89327 / r89329;
        return r89330;
}
↓
double f(double re, double im) {
        double r89331 = im;
        double r89332 = re;
        double r89333 = atan2(r89331, r89332);
        double r89334 = 10.0;
        double r89335 = log(r89334);
        double r89336 = r89333 / r89335;
        return r89336;
}

Error

Bits error versus re

Bits error versus im

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.8

    \[\frac{\tan^{-1}_* \frac{im}{re}}{\log 10}\]

  2. Final simplification0.8

    \[\leadsto \frac{\tan^{-1}_* \frac{im}{re}}{\log 10}\]

Reproduce

herbie shell --seed 2020089 
(FPCore (re im)
  :name "math.log10 on complex, imaginary part"
  :precision binary64
  (/ (atan2 im re) (log 10)))