\left(\left(x \cdot y + \frac{z \cdot t}{16}\right) - \frac{a \cdot b}{4}\right) + c\mathsf{fma}\left(z, \frac{t}{16}, \mathsf{fma}\left(y, x, \mathsf{fma}\left(-\frac{a}{4}, b, c\right)\right)\right)double f(double x, double y, double z, double t, double a, double b, double c) {
double r187262 = x;
double r187263 = y;
double r187264 = r187262 * r187263;
double r187265 = z;
double r187266 = t;
double r187267 = r187265 * r187266;
double r187268 = 16.0;
double r187269 = r187267 / r187268;
double r187270 = r187264 + r187269;
double r187271 = a;
double r187272 = b;
double r187273 = r187271 * r187272;
double r187274 = 4.0;
double r187275 = r187273 / r187274;
double r187276 = r187270 - r187275;
double r187277 = c;
double r187278 = r187276 + r187277;
return r187278;
}
double f(double x, double y, double z, double t, double a, double b, double c) {
double r187279 = z;
double r187280 = t;
double r187281 = 16.0;
double r187282 = r187280 / r187281;
double r187283 = y;
double r187284 = x;
double r187285 = a;
double r187286 = 4.0;
double r187287 = r187285 / r187286;
double r187288 = -r187287;
double r187289 = b;
double r187290 = c;
double r187291 = fma(r187288, r187289, r187290);
double r187292 = fma(r187283, r187284, r187291);
double r187293 = fma(r187279, r187282, r187292);
return r187293;
}



Bits error versus x



Bits error versus y



Bits error versus z



Bits error versus t



Bits error versus a



Bits error versus b



Bits error versus c
Initial program 0.2
Simplified0.0
Final simplification0.0
herbie shell --seed 2020081 +o rules:numerics
(FPCore (x y z t a b c)
:name "Diagrams.Solve.Polynomial:quartForm from diagrams-solve-0.1, C"
:precision binary64
(+ (- (+ (* x y) (/ (* z t) 16)) (/ (* a b) 4)) c))