Average Error: 0.0 → 0.0
Time: 789.0ms
Precision: 64
\[0.0 \le x \le 2\]
\[x + x \cdot x\]
\[x + x \cdot x\]
x + x \cdot x
x + x \cdot x
double f(double x) {
        double r94069 = x;
        double r94070 = r94069 * r94069;
        double r94071 = r94069 + r94070;
        return r94071;
}

double f(double x) {
        double r94072 = x;
        double r94073 = r94072 * r94072;
        double r94074 = r94072 + r94073;
        return r94074;
}

Error

Bits error versus x

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original0.0
Target0.0
Herbie0.0
\[\left(1 + x\right) \cdot x\]

Derivation

  1. Initial program 0.0

    \[x + x \cdot x\]
  2. Final simplification0.0

    \[\leadsto x + x \cdot x\]

Reproduce

herbie shell --seed 2020081 
(FPCore (x)
  :name "Expression 2, p15"
  :precision binary64
  :pre (<= 0.0 x 2)

  :herbie-target
  (* (+ 1 x) x)

  (+ x (* x x)))