Average Error: 0 → 0
Time: 434.0ms
Precision: 64
\[\left(x \cdot 16\right) \cdot x\]
\[\left(x \cdot 16\right) \cdot x\]
\left(x \cdot 16\right) \cdot x
\left(x \cdot 16\right) \cdot x
double f(double x) {
        double r170421 = x;
        double r170422 = 16.0;
        double r170423 = r170421 * r170422;
        double r170424 = r170423 * r170421;
        return r170424;
}

double f(double x) {
        double r170425 = x;
        double r170426 = 16.0;
        double r170427 = r170425 * r170426;
        double r170428 = r170427 * r170425;
        return r170428;
}

Error

Bits error versus x

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0

    \[\left(x \cdot 16\right) \cdot x\]
  2. Final simplification0

    \[\leadsto \left(x \cdot 16\right) \cdot x\]

Reproduce

herbie shell --seed 2020081 
(FPCore (x)
  :name "Graphics.Rasterific.CubicBezier:isSufficientlyFlat from Rasterific-0.6.1"
  :precision binary64
  (* (* x 16) x))