Average Error: 28.9 → 0.1
Time: 5.2s
Precision: 64
\[\log \left(N + 1\right) - \log N\]
\[\begin{array}{l} \mathbf{if}\;N \le 3345.38054805357797:\\ \;\;\;\;\log \left({N}^{3} + {1}^{3}\right) - \left(\log \left(N \cdot N + \left(1 \cdot 1 - N \cdot 1\right)\right) + \log N\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{{N}^{2}} \cdot \left(\frac{0.333333333333333315}{N} - 0.5\right) + \frac{1}{N}\\ \end{array}\]
\log \left(N + 1\right) - \log N
\begin{array}{l}
\mathbf{if}\;N \le 3345.38054805357797:\\
\;\;\;\;\log \left({N}^{3} + {1}^{3}\right) - \left(\log \left(N \cdot N + \left(1 \cdot 1 - N \cdot 1\right)\right) + \log N\right)\\

\mathbf{else}:\\
\;\;\;\;\frac{1}{{N}^{2}} \cdot \left(\frac{0.333333333333333315}{N} - 0.5\right) + \frac{1}{N}\\

\end{array}
double code(double N) {
	return (log((N + 1.0)) - log(N));
}
double code(double N) {
	double temp;
	if ((N <= 3345.380548053578)) {
		temp = (log((pow(N, 3.0) + pow(1.0, 3.0))) - (log(((N * N) + ((1.0 * 1.0) - (N * 1.0)))) + log(N)));
	} else {
		temp = (((1.0 / pow(N, 2.0)) * ((0.3333333333333333 / N) - 0.5)) + (1.0 / N));
	}
	return temp;
}

Error

Bits error versus N

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Split input into 2 regimes
  2. if N < 3345.380548053578

    1. Initial program 0.1

      \[\log \left(N + 1\right) - \log N\]
    2. Using strategy rm
    3. Applied flip3-+0.1

      \[\leadsto \log \color{blue}{\left(\frac{{N}^{3} + {1}^{3}}{N \cdot N + \left(1 \cdot 1 - N \cdot 1\right)}\right)} - \log N\]
    4. Applied log-div0.1

      \[\leadsto \color{blue}{\left(\log \left({N}^{3} + {1}^{3}\right) - \log \left(N \cdot N + \left(1 \cdot 1 - N \cdot 1\right)\right)\right)} - \log N\]
    5. Applied associate--l-0.1

      \[\leadsto \color{blue}{\log \left({N}^{3} + {1}^{3}\right) - \left(\log \left(N \cdot N + \left(1 \cdot 1 - N \cdot 1\right)\right) + \log N\right)}\]

    if 3345.380548053578 < N

    1. Initial program 59.5

      \[\log \left(N + 1\right) - \log N\]
    2. Taylor expanded around inf 0.1

      \[\leadsto \color{blue}{\left(0.333333333333333315 \cdot \frac{1}{{N}^{3}} + 1 \cdot \frac{1}{N}\right) - 0.5 \cdot \frac{1}{{N}^{2}}}\]
    3. Simplified0.1

      \[\leadsto \color{blue}{\frac{1}{{N}^{2}} \cdot \left(\frac{0.333333333333333315}{N} - 0.5\right) + \frac{1}{N}}\]
  3. Recombined 2 regimes into one program.
  4. Final simplification0.1

    \[\leadsto \begin{array}{l} \mathbf{if}\;N \le 3345.38054805357797:\\ \;\;\;\;\log \left({N}^{3} + {1}^{3}\right) - \left(\log \left(N \cdot N + \left(1 \cdot 1 - N \cdot 1\right)\right) + \log N\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{{N}^{2}} \cdot \left(\frac{0.333333333333333315}{N} - 0.5\right) + \frac{1}{N}\\ \end{array}\]

Reproduce

herbie shell --seed 2020066 
(FPCore (N)
  :name "2log (problem 3.3.6)"
  :precision binary64
  (- (log (+ N 1)) (log N)))