Average Error: 0.0 → 0.0
Time: 627.0ms
Precision: 64
\[x + x \cdot x\]
↓
\[x \cdot \left(1 + x\right)\]
x + x \cdot x
↓
x \cdot \left(1 + x\right)
double f(double x) {
        double r94280 = x;
        double r94281 = r94280 * r94280;
        double r94282 = r94280 + r94281;
        return r94282;
}
↓
double f(double x) {
        double r94283 = x;
        double r94284 = 1.0;
        double r94285 = r94284 + r94283;
        double r94286 = r94283 * r94285;
        return r94286;
}

Error

Bits error versus x

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.0

    \[x + x \cdot x\]
  2. Using strategy rm

  3. Applied *-un-lft-identity0.0

    \[\leadsto \color{blue}{1 \cdot x} + x \cdot x\]

  4. Applied distribute-rgt-out0.0

    \[\leadsto \color{blue}{x \cdot \left(1 + x\right)}\]

  5. Final simplification0.0

    \[\leadsto x \cdot \left(1 + x\right)\]

Reproduce

herbie shell --seed 2020064 
(FPCore (x)
  :name "Main:bigenough1 from B"
  :precision binary64
  (+ x (* x x)))