Average Error: 0.0 → 0.0
Time: 679.0ms
Precision: 64
\[e^{\left(x \cdot y\right) \cdot y}\]
↓
\[e^{\left(x \cdot y\right) \cdot y}\]
e^{\left(x \cdot y\right) \cdot y}
↓
e^{\left(x \cdot y\right) \cdot y}
double f(double x, double y) {
        double r200462 = x;
        double r200463 = y;
        double r200464 = r200462 * r200463;
        double r200465 = r200464 * r200463;
        double r200466 = exp(r200465);
        return r200466;
}
↓
double f(double x, double y) {
        double r200467 = x;
        double r200468 = y;
        double r200469 = r200467 * r200468;
        double r200470 = r200469 * r200468;
        double r200471 = exp(r200470);
        return r200471;
}

Error

Bits error versus x

Bits error versus y

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.0

    \[e^{\left(x \cdot y\right) \cdot y}\]

  2. Final simplification0.0

    \[\leadsto e^{\left(x \cdot y\right) \cdot y}\]

Reproduce

herbie shell --seed 2020062 +o rules:numerics
(FPCore (x y)
  :name "Data.Random.Distribution.Normal:normalF from random-fu-0.2.6.2"
  :precision binary64
  (exp (* (* x y) y)))