Average Error: 0.0 → 0.0
Time: 2.0s
Precision: 64
\[x \cdot e^{y \cdot y}\]
↓
\[x \cdot e^{y \cdot y}\]
x \cdot e^{y \cdot y}
↓
x \cdot e^{y \cdot y}
double f(double x, double y) {
        double r829913 = x;
        double r829914 = y;
        double r829915 = r829914 * r829914;
        double r829916 = exp(r829915);
        double r829917 = r829913 * r829916;
        return r829917;
}
↓
double f(double x, double y) {
        double r829918 = x;
        double r829919 = y;
        double r829920 = r829919 * r829919;
        double r829921 = exp(r829920);
        double r829922 = r829918 * r829921;
        return r829922;
}

Error

Bits error versus x

Bits error versus y

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original0.0
Target0.0
Herbie0.0
\[x \cdot {\left(e^{y}\right)}^{y}\]

Derivation

  1. Initial program 0.0

    \[x \cdot e^{y \cdot y}\]

  2. Final simplification0.0

    \[\leadsto x \cdot e^{y \cdot y}\]

Reproduce

herbie shell --seed 2020062 +o rules:numerics
(FPCore (x y)
  :name "Data.Number.Erf:$dmerfcx from erf-2.0.0.0"
  :precision binary64

  :herbie-target
  (* x (pow (exp y) y))

  (* x (exp (* y y))))