Average Error: 0 → 0
Time: 309.0ms
Precision: 64
\[\left(x \cdot 16\right) \cdot x\]
\[\left(x \cdot 16\right) \cdot x\]
\left(x \cdot 16\right) \cdot x
\left(x \cdot 16\right) \cdot x
double f(double x) {
        double r150291 = x;
        double r150292 = 16.0;
        double r150293 = r150291 * r150292;
        double r150294 = r150293 * r150291;
        return r150294;
}

double f(double x) {
        double r150295 = x;
        double r150296 = 16.0;
        double r150297 = r150295 * r150296;
        double r150298 = r150297 * r150295;
        return r150298;
}

Error

Bits error versus x

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0

    \[\left(x \cdot 16\right) \cdot x\]
  2. Final simplification0

    \[\leadsto \left(x \cdot 16\right) \cdot x\]

Reproduce

herbie shell --seed 2020060 +o rules:numerics
(FPCore (x)
  :name "Graphics.Rasterific.CubicBezier:isSufficientlyFlat from Rasterific-0.6.1"
  :precision binary64
  (* (* x 16) x))