Average Error: 0.0 → 0.0
Time: 4.0s
Precision: 64
\[\frac{-\left(f + n\right)}{f - n}\]
\[\frac{1}{\frac{f - n}{-\left(f + n\right)}}\]
\frac{-\left(f + n\right)}{f - n}
\frac{1}{\frac{f - n}{-\left(f + n\right)}}
double f(double f, double n) {
        double r16096 = f;
        double r16097 = n;
        double r16098 = r16096 + r16097;
        double r16099 = -r16098;
        double r16100 = r16096 - r16097;
        double r16101 = r16099 / r16100;
        return r16101;
}

double f(double f, double n) {
        double r16102 = 1.0;
        double r16103 = f;
        double r16104 = n;
        double r16105 = r16103 - r16104;
        double r16106 = r16103 + r16104;
        double r16107 = -r16106;
        double r16108 = r16105 / r16107;
        double r16109 = r16102 / r16108;
        return r16109;
}

Error

Bits error versus f

Bits error versus n

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.0

    \[\frac{-\left(f + n\right)}{f - n}\]
  2. Using strategy rm
  3. Applied clear-num0.0

    \[\leadsto \color{blue}{\frac{1}{\frac{f - n}{-\left(f + n\right)}}}\]
  4. Final simplification0.0

    \[\leadsto \frac{1}{\frac{f - n}{-\left(f + n\right)}}\]

Reproduce

herbie shell --seed 2020060 
(FPCore (f n)
  :name "subtraction fraction"
  :precision binary64
  (/ (- (+ f n)) (- f n)))