\left(\frac{\sqrt{2}}{4} \cdot \sqrt{1 - 3 \cdot \left(v \cdot v\right)}\right) \cdot \left(1 - v \cdot v\right)\left(\frac{\sqrt{2}}{4} \cdot \sqrt{1 - 3 \cdot \left(v \cdot v\right)}\right) \cdot \left(1 - v \cdot v\right)double f(double v) {
double r257776 = 2.0;
double r257777 = sqrt(r257776);
double r257778 = 4.0;
double r257779 = r257777 / r257778;
double r257780 = 1.0;
double r257781 = 3.0;
double r257782 = v;
double r257783 = r257782 * r257782;
double r257784 = r257781 * r257783;
double r257785 = r257780 - r257784;
double r257786 = sqrt(r257785);
double r257787 = r257779 * r257786;
double r257788 = r257780 - r257783;
double r257789 = r257787 * r257788;
return r257789;
}
double f(double v) {
double r257790 = 2.0;
double r257791 = sqrt(r257790);
double r257792 = 4.0;
double r257793 = r257791 / r257792;
double r257794 = 1.0;
double r257795 = 3.0;
double r257796 = v;
double r257797 = r257796 * r257796;
double r257798 = r257795 * r257797;
double r257799 = r257794 - r257798;
double r257800 = sqrt(r257799);
double r257801 = r257793 * r257800;
double r257802 = r257794 - r257797;
double r257803 = r257801 * r257802;
return r257803;
}



Bits error versus v
Results
Initial program 0.0
Final simplification0.0
herbie shell --seed 2020060 +o rules:numerics
(FPCore (v)
:name "Falkner and Boettcher, Appendix B, 2"
:precision binary64
(* (* (/ (sqrt 2) 4) (sqrt (- 1 (* 3 (* v v))))) (- 1 (* v v))))