Average Error: 60.2 → 3.4
Time: 10.6s
Precision: 64
\[-1 \lt \varepsilon \land \varepsilon \lt 1\]
\[\frac{\varepsilon \cdot \left(e^{\left(a + b\right) \cdot \varepsilon} - 1\right)}{\left(e^{a \cdot \varepsilon} - 1\right) \cdot \left(e^{b \cdot \varepsilon} - 1\right)}\]
\[\frac{1}{b} + \frac{1}{a}\]
\frac{\varepsilon \cdot \left(e^{\left(a + b\right) \cdot \varepsilon} - 1\right)}{\left(e^{a \cdot \varepsilon} - 1\right) \cdot \left(e^{b \cdot \varepsilon} - 1\right)}
\frac{1}{b} + \frac{1}{a}
double f(double a, double b, double eps) {
        double r102440 = eps;
        double r102441 = a;
        double r102442 = b;
        double r102443 = r102441 + r102442;
        double r102444 = r102443 * r102440;
        double r102445 = exp(r102444);
        double r102446 = 1.0;
        double r102447 = r102445 - r102446;
        double r102448 = r102440 * r102447;
        double r102449 = r102441 * r102440;
        double r102450 = exp(r102449);
        double r102451 = r102450 - r102446;
        double r102452 = r102442 * r102440;
        double r102453 = exp(r102452);
        double r102454 = r102453 - r102446;
        double r102455 = r102451 * r102454;
        double r102456 = r102448 / r102455;
        return r102456;
}

double f(double a, double b, double __attribute__((unused)) eps) {
        double r102457 = 1.0;
        double r102458 = b;
        double r102459 = r102457 / r102458;
        double r102460 = a;
        double r102461 = r102457 / r102460;
        double r102462 = r102459 + r102461;
        return r102462;
}

Error

Bits error versus a

Bits error versus b

Bits error versus eps

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original60.2
Target14.7
Herbie3.4
\[\frac{a + b}{a \cdot b}\]

Derivation

  1. Initial program 60.2

    \[\frac{\varepsilon \cdot \left(e^{\left(a + b\right) \cdot \varepsilon} - 1\right)}{\left(e^{a \cdot \varepsilon} - 1\right) \cdot \left(e^{b \cdot \varepsilon} - 1\right)}\]
  2. Taylor expanded around 0 3.4

    \[\leadsto \color{blue}{\frac{1}{b} + \frac{1}{a}}\]
  3. Final simplification3.4

    \[\leadsto \frac{1}{b} + \frac{1}{a}\]

Reproduce

herbie shell --seed 2020060 +o rules:numerics
(FPCore (a b eps)
  :name "expq3 (problem 3.4.2)"
  :precision binary64
  :pre (and (< -1 eps) (< eps 1))

  :herbie-target
  (/ (+ a b) (* a b))

  (/ (* eps (- (exp (* (+ a b) eps)) 1)) (* (- (exp (* a eps)) 1) (- (exp (* b eps)) 1))))