Average Error: 0.0 → 0.0
Time: 4.5s
Precision: 64
\[\frac{-\left(f + n\right)}{f - n}\]
\[\frac{1}{\frac{f - n}{-\left(f + n\right)}}\]
\frac{-\left(f + n\right)}{f - n}
\frac{1}{\frac{f - n}{-\left(f + n\right)}}
double f(double f, double n) {
        double r16097 = f;
        double r16098 = n;
        double r16099 = r16097 + r16098;
        double r16100 = -r16099;
        double r16101 = r16097 - r16098;
        double r16102 = r16100 / r16101;
        return r16102;
}

double f(double f, double n) {
        double r16103 = 1.0;
        double r16104 = f;
        double r16105 = n;
        double r16106 = r16104 - r16105;
        double r16107 = r16104 + r16105;
        double r16108 = -r16107;
        double r16109 = r16106 / r16108;
        double r16110 = r16103 / r16109;
        return r16110;
}

Error

Bits error versus f

Bits error versus n

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.0

    \[\frac{-\left(f + n\right)}{f - n}\]
  2. Using strategy rm
  3. Applied clear-num0.0

    \[\leadsto \color{blue}{\frac{1}{\frac{f - n}{-\left(f + n\right)}}}\]
  4. Final simplification0.0

    \[\leadsto \frac{1}{\frac{f - n}{-\left(f + n\right)}}\]

Reproduce

herbie shell --seed 2020060 
(FPCore (f n)
  :name "subtraction fraction"
  :precision binary64
  (/ (- (+ f n)) (- f n)))