Average Error: 25.1 → 8.7
Time: 6.7s
Precision: 64
\[x - \frac{\log \left(\left(1 - y\right) + y \cdot e^{z}\right)}{t}\]
\[\begin{array}{l} \mathbf{if}\;e^{z} \le 0.0:\\ \;\;\;\;x - \frac{2 \cdot \log \left(\sqrt[3]{1 - \left(1 - e^{z}\right) \cdot y}\right) + \log \left(\sqrt[3]{1 - \left(1 - e^{z}\right) \cdot y}\right)}{t}\\ \mathbf{else}:\\ \;\;\;\;x - \left(1 \cdot \frac{z \cdot y}{t} + \left(\frac{\log 1}{t} + 0.5 \cdot \frac{{z}^{2} \cdot y}{t}\right)\right)\\ \end{array}\]
x - \frac{\log \left(\left(1 - y\right) + y \cdot e^{z}\right)}{t}
\begin{array}{l}
\mathbf{if}\;e^{z} \le 0.0:\\
\;\;\;\;x - \frac{2 \cdot \log \left(\sqrt[3]{1 - \left(1 - e^{z}\right) \cdot y}\right) + \log \left(\sqrt[3]{1 - \left(1 - e^{z}\right) \cdot y}\right)}{t}\\

\mathbf{else}:\\
\;\;\;\;x - \left(1 \cdot \frac{z \cdot y}{t} + \left(\frac{\log 1}{t} + 0.5 \cdot \frac{{z}^{2} \cdot y}{t}\right)\right)\\

\end{array}
double code(double x, double y, double z, double t) {
	return (x - (log(((1.0 - y) + (y * exp(z)))) / t));
}
double code(double x, double y, double z, double t) {
	double temp;
	if ((exp(z) <= 0.0)) {
		temp = (x - (((2.0 * log(cbrt((1.0 - ((1.0 - exp(z)) * y))))) + log(cbrt((1.0 - ((1.0 - exp(z)) * y))))) / t));
	} else {
		temp = (x - ((1.0 * ((z * y) / t)) + ((log(1.0) / t) + (0.5 * ((pow(z, 2.0) * y) / t)))));
	}
	return temp;
}

Error

Bits error versus x

Bits error versus y

Bits error versus z

Bits error versus t

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original25.1
Target16.1
Herbie8.7
\[\begin{array}{l} \mathbf{if}\;z \lt -2.88746230882079466 \cdot 10^{119}:\\ \;\;\;\;\left(x - \frac{\frac{-0.5}{y \cdot t}}{z \cdot z}\right) - \frac{-0.5}{y \cdot t} \cdot \frac{\frac{2}{z}}{z \cdot z}\\ \mathbf{else}:\\ \;\;\;\;x - \frac{\log \left(1 + z \cdot y\right)}{t}\\ \end{array}\]

Derivation

  1. Split input into 2 regimes
  2. if (exp z) < 0.0

    1. Initial program 12.0

      \[x - \frac{\log \left(\left(1 - y\right) + y \cdot e^{z}\right)}{t}\]
    2. Using strategy rm
    3. Applied associate-+l-12.0

      \[\leadsto x - \frac{\log \color{blue}{\left(1 - \left(y - y \cdot e^{z}\right)\right)}}{t}\]
    4. Simplified12.0

      \[\leadsto x - \frac{\log \left(1 - \color{blue}{\left(1 - e^{z}\right) \cdot y}\right)}{t}\]
    5. Using strategy rm
    6. Applied add-cube-cbrt12.1

      \[\leadsto x - \frac{\log \color{blue}{\left(\left(\sqrt[3]{1 - \left(1 - e^{z}\right) \cdot y} \cdot \sqrt[3]{1 - \left(1 - e^{z}\right) \cdot y}\right) \cdot \sqrt[3]{1 - \left(1 - e^{z}\right) \cdot y}\right)}}{t}\]
    7. Applied log-prod12.1

      \[\leadsto x - \frac{\color{blue}{\log \left(\sqrt[3]{1 - \left(1 - e^{z}\right) \cdot y} \cdot \sqrt[3]{1 - \left(1 - e^{z}\right) \cdot y}\right) + \log \left(\sqrt[3]{1 - \left(1 - e^{z}\right) \cdot y}\right)}}{t}\]
    8. Simplified12.1

      \[\leadsto x - \frac{\color{blue}{2 \cdot \log \left(\sqrt[3]{1 - \left(1 - e^{z}\right) \cdot y}\right)} + \log \left(\sqrt[3]{1 - \left(1 - e^{z}\right) \cdot y}\right)}{t}\]

    if 0.0 < (exp z)

    1. Initial program 30.5

      \[x - \frac{\log \left(\left(1 - y\right) + y \cdot e^{z}\right)}{t}\]
    2. Taylor expanded around 0 7.3

      \[\leadsto x - \color{blue}{\left(1 \cdot \frac{z \cdot y}{t} + \left(\frac{\log 1}{t} + 0.5 \cdot \frac{{z}^{2} \cdot y}{t}\right)\right)}\]
  3. Recombined 2 regimes into one program.
  4. Final simplification8.7

    \[\leadsto \begin{array}{l} \mathbf{if}\;e^{z} \le 0.0:\\ \;\;\;\;x - \frac{2 \cdot \log \left(\sqrt[3]{1 - \left(1 - e^{z}\right) \cdot y}\right) + \log \left(\sqrt[3]{1 - \left(1 - e^{z}\right) \cdot y}\right)}{t}\\ \mathbf{else}:\\ \;\;\;\;x - \left(1 \cdot \frac{z \cdot y}{t} + \left(\frac{\log 1}{t} + 0.5 \cdot \frac{{z}^{2} \cdot y}{t}\right)\right)\\ \end{array}\]

Reproduce

herbie shell --seed 2020058 
(FPCore (x y z t)
  :name "System.Random.MWC.Distributions:truncatedExp from mwc-random-0.13.3.2"
  :precision binary64

  :herbie-target
  (if (< z -2.8874623088207947e+119) (- (- x (/ (/ (- 0.5) (* y t)) (* z z))) (* (/ (- 0.5) (* y t)) (/ (/ 2 z) (* z z)))) (- x (/ (log (+ 1 (* z y))) t)))

  (- x (/ (log (+ (- 1 y) (* y (exp z)))) t)))