Average Error: 11.4 → 5.2
Time: 2.7s
Precision: 64
\[\frac{a1 \cdot a2}{b1 \cdot b2}\]
\[\begin{array}{l} \mathbf{if}\;a1 \cdot a2 = -\infty \lor \neg \left(a1 \cdot a2 \le -4.0878819804843486 \cdot 10^{-254} \lor \neg \left(a1 \cdot a2 \le 1.7944304405375 \cdot 10^{-310} \lor \neg \left(a1 \cdot a2 \le 3.0403037297418217 \cdot 10^{246}\right)\right)\right):\\ \;\;\;\;\frac{a1}{b1} \cdot \frac{a2}{b2}\\ \mathbf{else}:\\ \;\;\;\;\left(a1 \cdot a2\right) \cdot \frac{\frac{1}{b1}}{b2}\\ \end{array}\]
\frac{a1 \cdot a2}{b1 \cdot b2}
\begin{array}{l}
\mathbf{if}\;a1 \cdot a2 = -\infty \lor \neg \left(a1 \cdot a2 \le -4.0878819804843486 \cdot 10^{-254} \lor \neg \left(a1 \cdot a2 \le 1.7944304405375 \cdot 10^{-310} \lor \neg \left(a1 \cdot a2 \le 3.0403037297418217 \cdot 10^{246}\right)\right)\right):\\
\;\;\;\;\frac{a1}{b1} \cdot \frac{a2}{b2}\\

\mathbf{else}:\\
\;\;\;\;\left(a1 \cdot a2\right) \cdot \frac{\frac{1}{b1}}{b2}\\

\end{array}
double code(double a1, double a2, double b1, double b2) {
	return ((a1 * a2) / (b1 * b2));
}
double code(double a1, double a2, double b1, double b2) {
	double temp;
	if ((((a1 * a2) <= -inf.0) || !(((a1 * a2) <= -4.0878819804843486e-254) || !(((a1 * a2) <= 1.7944304405375e-310) || !((a1 * a2) <= 3.0403037297418217e+246))))) {
		temp = ((a1 / b1) * (a2 / b2));
	} else {
		temp = ((a1 * a2) * ((1.0 / b1) / b2));
	}
	return temp;
}

Error

Bits error versus a1

Bits error versus a2

Bits error versus b1

Bits error versus b2

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original11.4
Target11.0
Herbie5.2
\[\frac{a1}{b1} \cdot \frac{a2}{b2}\]

Derivation

  1. Split input into 2 regimes
  2. if (* a1 a2) < -inf.0 or -4.0878819804843486e-254 < (* a1 a2) < 1.7944304405375e-310 or 3.0403037297418217e+246 < (* a1 a2)

    1. Initial program 27.6

      \[\frac{a1 \cdot a2}{b1 \cdot b2}\]
    2. Using strategy rm
    3. Applied times-frac4.3

      \[\leadsto \color{blue}{\frac{a1}{b1} \cdot \frac{a2}{b2}}\]

    if -inf.0 < (* a1 a2) < -4.0878819804843486e-254 or 1.7944304405375e-310 < (* a1 a2) < 3.0403037297418217e+246

    1. Initial program 5.5

      \[\frac{a1 \cdot a2}{b1 \cdot b2}\]
    2. Using strategy rm
    3. Applied div-inv5.8

      \[\leadsto \color{blue}{\left(a1 \cdot a2\right) \cdot \frac{1}{b1 \cdot b2}}\]
    4. Using strategy rm
    5. Applied associate-/r*5.5

      \[\leadsto \left(a1 \cdot a2\right) \cdot \color{blue}{\frac{\frac{1}{b1}}{b2}}\]
  3. Recombined 2 regimes into one program.
  4. Final simplification5.2

    \[\leadsto \begin{array}{l} \mathbf{if}\;a1 \cdot a2 = -\infty \lor \neg \left(a1 \cdot a2 \le -4.0878819804843486 \cdot 10^{-254} \lor \neg \left(a1 \cdot a2 \le 1.7944304405375 \cdot 10^{-310} \lor \neg \left(a1 \cdot a2 \le 3.0403037297418217 \cdot 10^{246}\right)\right)\right):\\ \;\;\;\;\frac{a1}{b1} \cdot \frac{a2}{b2}\\ \mathbf{else}:\\ \;\;\;\;\left(a1 \cdot a2\right) \cdot \frac{\frac{1}{b1}}{b2}\\ \end{array}\]

Reproduce

herbie shell --seed 2020057 +o rules:numerics
(FPCore (a1 a2 b1 b2)
  :name "Quotient of products"
  :precision binary64

  :herbie-target
  (* (/ a1 b1) (/ a2 b2))

  (/ (* a1 a2) (* b1 b2)))