Average Error: 11.4 → 5.2
Time: 2.7s
Precision: 64
\[\frac{a1 \cdot a2}{b1 \cdot b2}\]
\[\begin{array}{l} \mathbf{if}\;a1 \cdot a2 = -\infty \lor \neg \left(a1 \cdot a2 \le -4.0878819804843486 \cdot 10^{-254} \lor \neg \left(a1 \cdot a2 \le 1.7944304405375 \cdot 10^{-310} \lor \neg \left(a1 \cdot a2 \le 3.0403037297418217 \cdot 10^{246}\right)\right)\right):\\ \;\;\;\;\frac{a1}{b1} \cdot \frac{a2}{b2}\\ \mathbf{else}:\\ \;\;\;\;\left(a1 \cdot a2\right) \cdot \frac{\frac{1}{b1}}{b2}\\ \end{array}\]
\frac{a1 \cdot a2}{b1 \cdot b2}
\begin{array}{l}
\mathbf{if}\;a1 \cdot a2 = -\infty \lor \neg \left(a1 \cdot a2 \le -4.0878819804843486 \cdot 10^{-254} \lor \neg \left(a1 \cdot a2 \le 1.7944304405375 \cdot 10^{-310} \lor \neg \left(a1 \cdot a2 \le 3.0403037297418217 \cdot 10^{246}\right)\right)\right):\\
\;\;\;\;\frac{a1}{b1} \cdot \frac{a2}{b2}\\

\mathbf{else}:\\
\;\;\;\;\left(a1 \cdot a2\right) \cdot \frac{\frac{1}{b1}}{b2}\\

\end{array}
double f(double a1, double a2, double b1, double b2) {
        double r133634 = a1;
        double r133635 = a2;
        double r133636 = r133634 * r133635;
        double r133637 = b1;
        double r133638 = b2;
        double r133639 = r133637 * r133638;
        double r133640 = r133636 / r133639;
        return r133640;
}

double f(double a1, double a2, double b1, double b2) {
        double r133641 = a1;
        double r133642 = a2;
        double r133643 = r133641 * r133642;
        double r133644 = -inf.0;
        bool r133645 = r133643 <= r133644;
        double r133646 = -4.0878819804843486e-254;
        bool r133647 = r133643 <= r133646;
        double r133648 = 1.7944304405375e-310;
        bool r133649 = r133643 <= r133648;
        double r133650 = 3.0403037297418217e+246;
        bool r133651 = r133643 <= r133650;
        double r133652 = !r133651;
        bool r133653 = r133649 || r133652;
        double r133654 = !r133653;
        bool r133655 = r133647 || r133654;
        double r133656 = !r133655;
        bool r133657 = r133645 || r133656;
        double r133658 = b1;
        double r133659 = r133641 / r133658;
        double r133660 = b2;
        double r133661 = r133642 / r133660;
        double r133662 = r133659 * r133661;
        double r133663 = 1.0;
        double r133664 = r133663 / r133658;
        double r133665 = r133664 / r133660;
        double r133666 = r133643 * r133665;
        double r133667 = r133657 ? r133662 : r133666;
        return r133667;
}

Error

Bits error versus a1

Bits error versus a2

Bits error versus b1

Bits error versus b2

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original11.4
Target11.0
Herbie5.2
\[\frac{a1}{b1} \cdot \frac{a2}{b2}\]

Derivation

  1. Split input into 2 regimes
  2. if (* a1 a2) < -inf.0 or -4.0878819804843486e-254 < (* a1 a2) < 1.7944304405375e-310 or 3.0403037297418217e+246 < (* a1 a2)

    1. Initial program 27.6

      \[\frac{a1 \cdot a2}{b1 \cdot b2}\]
    2. Using strategy rm
    3. Applied times-frac4.3

      \[\leadsto \color{blue}{\frac{a1}{b1} \cdot \frac{a2}{b2}}\]

    if -inf.0 < (* a1 a2) < -4.0878819804843486e-254 or 1.7944304405375e-310 < (* a1 a2) < 3.0403037297418217e+246

    1. Initial program 5.5

      \[\frac{a1 \cdot a2}{b1 \cdot b2}\]
    2. Using strategy rm
    3. Applied div-inv5.8

      \[\leadsto \color{blue}{\left(a1 \cdot a2\right) \cdot \frac{1}{b1 \cdot b2}}\]
    4. Using strategy rm
    5. Applied associate-/r*5.5

      \[\leadsto \left(a1 \cdot a2\right) \cdot \color{blue}{\frac{\frac{1}{b1}}{b2}}\]
  3. Recombined 2 regimes into one program.
  4. Final simplification5.2

    \[\leadsto \begin{array}{l} \mathbf{if}\;a1 \cdot a2 = -\infty \lor \neg \left(a1 \cdot a2 \le -4.0878819804843486 \cdot 10^{-254} \lor \neg \left(a1 \cdot a2 \le 1.7944304405375 \cdot 10^{-310} \lor \neg \left(a1 \cdot a2 \le 3.0403037297418217 \cdot 10^{246}\right)\right)\right):\\ \;\;\;\;\frac{a1}{b1} \cdot \frac{a2}{b2}\\ \mathbf{else}:\\ \;\;\;\;\left(a1 \cdot a2\right) \cdot \frac{\frac{1}{b1}}{b2}\\ \end{array}\]

Reproduce

herbie shell --seed 2020057 +o rules:numerics
(FPCore (a1 a2 b1 b2)
  :name "Quotient of products"
  :precision binary64

  :herbie-target
  (* (/ a1 b1) (/ a2 b2))

  (/ (* a1 a2) (* b1 b2)))