Average Error: 0.6 → 0.5
Time: 3.8s
Precision: 64
\[\frac{e^{a}}{e^{a} + e^{b}}\]
\[\mathsf{expm1}\left(\mathsf{log1p}\left(e^{a - \log \left(e^{a} + e^{b}\right)}\right)\right)\]
\frac{e^{a}}{e^{a} + e^{b}}
\mathsf{expm1}\left(\mathsf{log1p}\left(e^{a - \log \left(e^{a} + e^{b}\right)}\right)\right)
double f(double a, double b) {
        double r168015 = a;
        double r168016 = exp(r168015);
        double r168017 = b;
        double r168018 = exp(r168017);
        double r168019 = r168016 + r168018;
        double r168020 = r168016 / r168019;
        return r168020;
}

double f(double a, double b) {
        double r168021 = a;
        double r168022 = exp(r168021);
        double r168023 = b;
        double r168024 = exp(r168023);
        double r168025 = r168022 + r168024;
        double r168026 = log(r168025);
        double r168027 = r168021 - r168026;
        double r168028 = exp(r168027);
        double r168029 = log1p(r168028);
        double r168030 = expm1(r168029);
        return r168030;
}

Error

Bits error versus a

Bits error versus b

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original0.6
Target0.0
Herbie0.5
\[\frac{1}{1 + e^{b - a}}\]

Derivation

  1. Initial program 0.6

    \[\frac{e^{a}}{e^{a} + e^{b}}\]
  2. Using strategy rm
  3. Applied add-exp-log0.6

    \[\leadsto \frac{e^{a}}{\color{blue}{e^{\log \left(e^{a} + e^{b}\right)}}}\]
  4. Applied div-exp0.5

    \[\leadsto \color{blue}{e^{a - \log \left(e^{a} + e^{b}\right)}}\]
  5. Using strategy rm
  6. Applied expm1-log1p-u0.5

    \[\leadsto \color{blue}{\mathsf{expm1}\left(\mathsf{log1p}\left(e^{a - \log \left(e^{a} + e^{b}\right)}\right)\right)}\]
  7. Final simplification0.5

    \[\leadsto \mathsf{expm1}\left(\mathsf{log1p}\left(e^{a - \log \left(e^{a} + e^{b}\right)}\right)\right)\]

Reproduce

herbie shell --seed 2020056 +o rules:numerics
(FPCore (a b)
  :name "Quotient of sum of exps"
  :precision binary64

  :herbie-target
  (/ 1 (+ 1 (exp (- b a))))

  (/ (exp a) (+ (exp a) (exp b))))