Average Error: 0.0 → 0.0
Time: 860.0ms
Precision: 64
\[x \cdot \left(1 - x \cdot 0.5\right)\]
↓
\[x \cdot \left(1 - x \cdot 0.5\right)\]
x \cdot \left(1 - x \cdot 0.5\right)
↓
x \cdot \left(1 - x \cdot 0.5\right)
double f(double x) {
        double r54027 = x;
        double r54028 = 1.0;
        double r54029 = 0.5;
        double r54030 = r54027 * r54029;
        double r54031 = r54028 - r54030;
        double r54032 = r54027 * r54031;
        return r54032;
}
↓
double f(double x) {
        double r54033 = x;
        double r54034 = 1.0;
        double r54035 = 0.5;
        double r54036 = r54033 * r54035;
        double r54037 = r54034 - r54036;
        double r54038 = r54033 * r54037;
        return r54038;
}

Error

Bits error versus x

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.0

    \[x \cdot \left(1 - x \cdot 0.5\right)\]

  2. Final simplification0.0

    \[\leadsto x \cdot \left(1 - x \cdot 0.5\right)\]

Reproduce

herbie shell --seed 2020056 +o rules:numerics
(FPCore (x)
  :name "Numeric.SpecFunctions:log1p from math-functions-0.1.5.2, B"
  :precision binary64
  (* x (- 1 (* x 0.5))))