Average Error: 0.6 → 0.5
Time: 4.0s
Precision: 64
\[\frac{e^{a}}{e^{a} + e^{b}}\]
\[\mathsf{expm1}\left(\mathsf{log1p}\left(e^{a - \log \left(e^{a} + e^{b}\right)}\right)\right)\]
\frac{e^{a}}{e^{a} + e^{b}}
\mathsf{expm1}\left(\mathsf{log1p}\left(e^{a - \log \left(e^{a} + e^{b}\right)}\right)\right)
double f(double a, double b) {
        double r158034 = a;
        double r158035 = exp(r158034);
        double r158036 = b;
        double r158037 = exp(r158036);
        double r158038 = r158035 + r158037;
        double r158039 = r158035 / r158038;
        return r158039;
}

double f(double a, double b) {
        double r158040 = a;
        double r158041 = exp(r158040);
        double r158042 = b;
        double r158043 = exp(r158042);
        double r158044 = r158041 + r158043;
        double r158045 = log(r158044);
        double r158046 = r158040 - r158045;
        double r158047 = exp(r158046);
        double r158048 = log1p(r158047);
        double r158049 = expm1(r158048);
        return r158049;
}

Error

Bits error versus a

Bits error versus b

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original0.6
Target0.0
Herbie0.5
\[\frac{1}{1 + e^{b - a}}\]

Derivation

  1. Initial program 0.6

    \[\frac{e^{a}}{e^{a} + e^{b}}\]
  2. Using strategy rm
  3. Applied add-exp-log0.6

    \[\leadsto \frac{e^{a}}{\color{blue}{e^{\log \left(e^{a} + e^{b}\right)}}}\]
  4. Applied div-exp0.5

    \[\leadsto \color{blue}{e^{a - \log \left(e^{a} + e^{b}\right)}}\]
  5. Using strategy rm
  6. Applied expm1-log1p-u0.5

    \[\leadsto \color{blue}{\mathsf{expm1}\left(\mathsf{log1p}\left(e^{a - \log \left(e^{a} + e^{b}\right)}\right)\right)}\]
  7. Final simplification0.5

    \[\leadsto \mathsf{expm1}\left(\mathsf{log1p}\left(e^{a - \log \left(e^{a} + e^{b}\right)}\right)\right)\]

Reproduce

herbie shell --seed 2020056 +o rules:numerics
(FPCore (a b)
  :name "Quotient of sum of exps"
  :precision binary64

  :herbie-target
  (/ 1 (+ 1 (exp (- b a))))

  (/ (exp a) (+ (exp a) (exp b))))