Average Error: 0.0 → 0.0
Time: 817.0ms
Precision: 64
\[x \cdot \left(1 - x \cdot 0.5\right)\]
↓
\[x \cdot \left(1 - x \cdot 0.5\right)\]
x \cdot \left(1 - x \cdot 0.5\right)
↓
x \cdot \left(1 - x \cdot 0.5\right)
double f(double x) {
        double r49337 = x;
        double r49338 = 1.0;
        double r49339 = 0.5;
        double r49340 = r49337 * r49339;
        double r49341 = r49338 - r49340;
        double r49342 = r49337 * r49341;
        return r49342;
}
↓
double f(double x) {
        double r49343 = x;
        double r49344 = 1.0;
        double r49345 = 0.5;
        double r49346 = r49343 * r49345;
        double r49347 = r49344 - r49346;
        double r49348 = r49343 * r49347;
        return r49348;
}

Error

Bits error versus x

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Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.0

    \[x \cdot \left(1 - x \cdot 0.5\right)\]

  2. Final simplification0.0

    \[\leadsto x \cdot \left(1 - x \cdot 0.5\right)\]

Reproduce

herbie shell --seed 2020056 
(FPCore (x)
  :name "Numeric.SpecFunctions:log1p from math-functions-0.1.5.2, B"
  :precision binary64
  (* x (- 1 (* x 0.5))))