Average Error: 60.3 → 3.4
Time: 9.1s
Precision: 64
\[-1 \lt \varepsilon \land \varepsilon \lt 1\]
\[\frac{\varepsilon \cdot \left(e^{\left(a + b\right) \cdot \varepsilon} - 1\right)}{\left(e^{a \cdot \varepsilon} - 1\right) \cdot \left(e^{b \cdot \varepsilon} - 1\right)}\]
\[\frac{1}{b} + \frac{1}{a}\]
\frac{\varepsilon \cdot \left(e^{\left(a + b\right) \cdot \varepsilon} - 1\right)}{\left(e^{a \cdot \varepsilon} - 1\right) \cdot \left(e^{b \cdot \varepsilon} - 1\right)}
\frac{1}{b} + \frac{1}{a}
double f(double a, double b, double eps) {
        double r91759 = eps;
        double r91760 = a;
        double r91761 = b;
        double r91762 = r91760 + r91761;
        double r91763 = r91762 * r91759;
        double r91764 = exp(r91763);
        double r91765 = 1.0;
        double r91766 = r91764 - r91765;
        double r91767 = r91759 * r91766;
        double r91768 = r91760 * r91759;
        double r91769 = exp(r91768);
        double r91770 = r91769 - r91765;
        double r91771 = r91761 * r91759;
        double r91772 = exp(r91771);
        double r91773 = r91772 - r91765;
        double r91774 = r91770 * r91773;
        double r91775 = r91767 / r91774;
        return r91775;
}

double f(double a, double b, double __attribute__((unused)) eps) {
        double r91776 = 1.0;
        double r91777 = b;
        double r91778 = r91776 / r91777;
        double r91779 = a;
        double r91780 = r91776 / r91779;
        double r91781 = r91778 + r91780;
        return r91781;
}

Error

Bits error versus a

Bits error versus b

Bits error versus eps

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original60.3
Target15.2
Herbie3.4
\[\frac{a + b}{a \cdot b}\]

Derivation

  1. Initial program 60.3

    \[\frac{\varepsilon \cdot \left(e^{\left(a + b\right) \cdot \varepsilon} - 1\right)}{\left(e^{a \cdot \varepsilon} - 1\right) \cdot \left(e^{b \cdot \varepsilon} - 1\right)}\]
  2. Taylor expanded around 0 3.4

    \[\leadsto \color{blue}{\frac{1}{b} + \frac{1}{a}}\]
  3. Final simplification3.4

    \[\leadsto \frac{1}{b} + \frac{1}{a}\]

Reproduce

herbie shell --seed 2020049 +o rules:numerics
(FPCore (a b eps)
  :name "expq3 (problem 3.4.2)"
  :precision binary64
  :pre (and (< -1 eps) (< eps 1))

  :herbie-target
  (/ (+ a b) (* a b))

  (/ (* eps (- (exp (* (+ a b) eps)) 1)) (* (- (exp (* a eps)) 1) (- (exp (* b eps)) 1))))