Average Error: 60.3 → 3.4
Time: 8.8s
Precision: 64
\[-1 \lt \varepsilon \land \varepsilon \lt 1\]
\[\frac{\varepsilon \cdot \left(e^{\left(a + b\right) \cdot \varepsilon} - 1\right)}{\left(e^{a \cdot \varepsilon} - 1\right) \cdot \left(e^{b \cdot \varepsilon} - 1\right)}\]
\[\frac{1}{b} + \frac{1}{a}\]
\frac{\varepsilon \cdot \left(e^{\left(a + b\right) \cdot \varepsilon} - 1\right)}{\left(e^{a \cdot \varepsilon} - 1\right) \cdot \left(e^{b \cdot \varepsilon} - 1\right)}
\frac{1}{b} + \frac{1}{a}
double f(double a, double b, double eps) {
        double r98620 = eps;
        double r98621 = a;
        double r98622 = b;
        double r98623 = r98621 + r98622;
        double r98624 = r98623 * r98620;
        double r98625 = exp(r98624);
        double r98626 = 1.0;
        double r98627 = r98625 - r98626;
        double r98628 = r98620 * r98627;
        double r98629 = r98621 * r98620;
        double r98630 = exp(r98629);
        double r98631 = r98630 - r98626;
        double r98632 = r98622 * r98620;
        double r98633 = exp(r98632);
        double r98634 = r98633 - r98626;
        double r98635 = r98631 * r98634;
        double r98636 = r98628 / r98635;
        return r98636;
}

double f(double a, double b, double __attribute__((unused)) eps) {
        double r98637 = 1.0;
        double r98638 = b;
        double r98639 = r98637 / r98638;
        double r98640 = a;
        double r98641 = r98637 / r98640;
        double r98642 = r98639 + r98641;
        return r98642;
}

Error

Bits error versus a

Bits error versus b

Bits error versus eps

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original60.3
Target15.2
Herbie3.4
\[\frac{a + b}{a \cdot b}\]

Derivation

  1. Initial program 60.3

    \[\frac{\varepsilon \cdot \left(e^{\left(a + b\right) \cdot \varepsilon} - 1\right)}{\left(e^{a \cdot \varepsilon} - 1\right) \cdot \left(e^{b \cdot \varepsilon} - 1\right)}\]
  2. Taylor expanded around 0 3.4

    \[\leadsto \color{blue}{\frac{1}{b} + \frac{1}{a}}\]
  3. Final simplification3.4

    \[\leadsto \frac{1}{b} + \frac{1}{a}\]

Reproduce

herbie shell --seed 2020049 
(FPCore (a b eps)
  :name "expq3 (problem 3.4.2)"
  :precision binary64
  :pre (and (< -1 eps) (< eps 1))

  :herbie-target
  (/ (+ a b) (* a b))

  (/ (* eps (- (exp (* (+ a b) eps)) 1)) (* (- (exp (* a eps)) 1) (- (exp (* b eps)) 1))))