\left({\left(a \cdot a + b \cdot b\right)}^{2} + 4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 + a\right) + \left(b \cdot b\right) \cdot \left(1 - 3 \cdot a\right)\right)\right) - 1\mathsf{fma}\left(4, \mathsf{fma}\left(1, \mathsf{fma}\left(a, a, b \cdot b\right), {a}^{3}\right), {\left(\mathsf{fma}\left(a, a, b \cdot b\right)\right)}^{2}\right) - 1double f(double a, double b) {
double r187175 = a;
double r187176 = r187175 * r187175;
double r187177 = b;
double r187178 = r187177 * r187177;
double r187179 = r187176 + r187178;
double r187180 = 2.0;
double r187181 = pow(r187179, r187180);
double r187182 = 4.0;
double r187183 = 1.0;
double r187184 = r187183 + r187175;
double r187185 = r187176 * r187184;
double r187186 = 3.0;
double r187187 = r187186 * r187175;
double r187188 = r187183 - r187187;
double r187189 = r187178 * r187188;
double r187190 = r187185 + r187189;
double r187191 = r187182 * r187190;
double r187192 = r187181 + r187191;
double r187193 = r187192 - r187183;
return r187193;
}
double f(double a, double b) {
double r187194 = 4.0;
double r187195 = 1.0;
double r187196 = a;
double r187197 = b;
double r187198 = r187197 * r187197;
double r187199 = fma(r187196, r187196, r187198);
double r187200 = 3.0;
double r187201 = pow(r187196, r187200);
double r187202 = fma(r187195, r187199, r187201);
double r187203 = 2.0;
double r187204 = pow(r187199, r187203);
double r187205 = fma(r187194, r187202, r187204);
double r187206 = r187205 - r187195;
return r187206;
}



Bits error versus a



Bits error versus b
Initial program 0.2
Simplified0.2
Taylor expanded around 0 0.2
Simplified0.2
Final simplification0.2
herbie shell --seed 2020047 +o rules:numerics
(FPCore (a b)
:name "Bouland and Aaronson, Equation (25)"
:precision binary64
(- (+ (pow (+ (* a a) (* b b)) 2) (* 4 (+ (* (* a a) (+ 1 a)) (* (* b b) (- 1 (* 3 a)))))) 1))