Average Error: 0.0 → 0.0
Time: 3.3s
Precision: 64
\[x \cdot \left(1 - x \cdot 0.5\right)\]
↓
\[x \cdot \left(1 - x \cdot 0.5\right)\]
x \cdot \left(1 - x \cdot 0.5\right)
↓
x \cdot \left(1 - x \cdot 0.5\right)
double f(double x) {
        double r54577 = x;
        double r54578 = 1.0;
        double r54579 = 0.5;
        double r54580 = r54577 * r54579;
        double r54581 = r54578 - r54580;
        double r54582 = r54577 * r54581;
        return r54582;
}
↓
double f(double x) {
        double r54583 = x;
        double r54584 = 1.0;
        double r54585 = 0.5;
        double r54586 = r54583 * r54585;
        double r54587 = r54584 - r54586;
        double r54588 = r54583 * r54587;
        return r54588;
}

Error

Bits error versus x

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.0

    \[x \cdot \left(1 - x \cdot 0.5\right)\]

  2. Final simplification0.0

    \[\leadsto x \cdot \left(1 - x \cdot 0.5\right)\]

Reproduce

herbie shell --seed 2020047 +o rules:numerics
(FPCore (x)
  :name "Numeric.SpecFunctions:log1p from math-functions-0.1.5.2, B"
  :precision binary64
  (* x (- 1 (* x 0.5))))