Average Error: 0 → 0
Time: 326.0ms
Precision: 64
\[\left(x \cdot 2\right) \cdot x\]
↓
\[\left(x \cdot 2\right) \cdot x\]
\left(x \cdot 2\right) \cdot x
↓
\left(x \cdot 2\right) \cdot x
double f(double x) {
        double r546708 = x;
        double r546709 = 2.0;
        double r546710 = r546708 * r546709;
        double r546711 = r546710 * r546708;
        return r546711;
}
↓
double f(double x) {
        double r546712 = x;
        double r546713 = 2.0;
        double r546714 = r546712 * r546713;
        double r546715 = r546714 * r546712;
        return r546715;
}

Error

Bits error versus x

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original0
Target0
Herbie0
\[\left(2 \cdot x\right) \cdot x\]

Derivation

  1. Initial program 0

    \[\left(x \cdot 2\right) \cdot x\]

  2. Final simplification0

    \[\leadsto \left(x \cdot 2\right) \cdot x\]

Reproduce

herbie shell --seed 2020047 +o rules:numerics
(FPCore (x)
  :name "Numeric.Log:$cexpm1 from log-domain-0.10.2.1, A"
  :precision binary64

  :herbie-target
  (* (* 2 x) x)

  (* (* x 2) x))