Average Error: 0.0 → 0.0
Time: 14.0s
Precision: 64
\[x \cdot e^{y \cdot y}\]
↓
\[x \cdot e^{y \cdot y}\]
x \cdot e^{y \cdot y}
↓
x \cdot e^{y \cdot y}
double f(double x, double y) {
        double r1072833 = x;
        double r1072834 = y;
        double r1072835 = r1072834 * r1072834;
        double r1072836 = exp(r1072835);
        double r1072837 = r1072833 * r1072836;
        return r1072837;
}
↓
double f(double x, double y) {
        double r1072838 = x;
        double r1072839 = y;
        double r1072840 = r1072839 * r1072839;
        double r1072841 = exp(r1072840);
        double r1072842 = r1072838 * r1072841;
        return r1072842;
}

Error

Bits error versus x

Bits error versus y

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original0.0
Target0.0
Herbie0.0
\[x \cdot {\left(e^{y}\right)}^{y}\]

Derivation

  1. Initial program 0.0

    \[x \cdot e^{y \cdot y}\]

  2. Final simplification0.0

    \[\leadsto x \cdot e^{y \cdot y}\]

Reproduce

herbie shell --seed 2020047 
(FPCore (x y)
  :name "Data.Number.Erf:$dmerfcx from erf-2.0.0.0"
  :precision binary64

  :herbie-target
  (* x (pow (exp y) y))

  (* x (exp (* y y))))