Average Error: 0.0 → 0.0
Time: 4.0s
Precision: 64
\[x \cdot \left(1 - x \cdot 0.5\right)\]
↓
\[x \cdot \left(1 - x \cdot 0.5\right)\]
x \cdot \left(1 - x \cdot 0.5\right)
↓
x \cdot \left(1 - x \cdot 0.5\right)
double f(double x) {
        double r44577 = x;
        double r44578 = 1.0;
        double r44579 = 0.5;
        double r44580 = r44577 * r44579;
        double r44581 = r44578 - r44580;
        double r44582 = r44577 * r44581;
        return r44582;
}
↓
double f(double x) {
        double r44583 = x;
        double r44584 = 1.0;
        double r44585 = 0.5;
        double r44586 = r44583 * r44585;
        double r44587 = r44584 - r44586;
        double r44588 = r44583 * r44587;
        return r44588;
}

Error

Bits error versus x

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.0

    \[x \cdot \left(1 - x \cdot 0.5\right)\]

  2. Final simplification0.0

    \[\leadsto x \cdot \left(1 - x \cdot 0.5\right)\]

Reproduce

herbie shell --seed 2020047 +o rules:numerics
(FPCore (x)
  :name "Numeric.SpecFunctions:log1p from math-functions-0.1.5.2, B"
  :precision binary64
  (* x (- 1 (* x 0.5))))