Average Error: 0.3 → 0
Time: 444.0ms
Precision: 64
\[d \cdot 10 + d \cdot 20\]
\[30 \cdot d\]
d \cdot 10 + d \cdot 20
30 \cdot d
double f(double d) {
        double r279312 = d;
        double r279313 = 10.0;
        double r279314 = r279312 * r279313;
        double r279315 = 20.0;
        double r279316 = r279312 * r279315;
        double r279317 = r279314 + r279316;
        return r279317;
}

double f(double d) {
        double r279318 = 30.0;
        double r279319 = d;
        double r279320 = r279318 * r279319;
        return r279320;
}

Error

Bits error versus d

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original0.3
Target0
Herbie0
\[d \cdot 30\]

Derivation

  1. Initial program 0.3

    \[d \cdot 10 + d \cdot 20\]
  2. Simplified0.1

    \[\leadsto \color{blue}{\mathsf{fma}\left(d, 10, d \cdot 20\right)}\]
  3. Taylor expanded around 0 0

    \[\leadsto \color{blue}{30 \cdot d}\]
  4. Final simplification0

    \[\leadsto 30 \cdot d\]

Reproduce

herbie shell --seed 2020047 +o rules:numerics
(FPCore (d)
  :name "FastMath test1"
  :precision binary64

  :herbie-target
  (* d 30)

  (+ (* d 10) (* d 20)))