Average Error: 0.0 → 0.0
Time: 824.0ms
Precision: 64
\[x \cdot \left(1 - x \cdot 0.5\right)\]
↓
\[x \cdot \left(1 - x \cdot 0.5\right)\]
x \cdot \left(1 - x \cdot 0.5\right)
↓
x \cdot \left(1 - x \cdot 0.5\right)
double f(double x) {
        double r32273 = x;
        double r32274 = 1.0;
        double r32275 = 0.5;
        double r32276 = r32273 * r32275;
        double r32277 = r32274 - r32276;
        double r32278 = r32273 * r32277;
        return r32278;
}
↓
double f(double x) {
        double r32279 = x;
        double r32280 = 1.0;
        double r32281 = 0.5;
        double r32282 = r32279 * r32281;
        double r32283 = r32280 - r32282;
        double r32284 = r32279 * r32283;
        return r32284;
}

Error

Bits error versus x

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.0

    \[x \cdot \left(1 - x \cdot 0.5\right)\]

  2. Final simplification0.0

    \[\leadsto x \cdot \left(1 - x \cdot 0.5\right)\]

Reproduce

herbie shell --seed 2020047 
(FPCore (x)
  :name "Numeric.SpecFunctions:log1p from math-functions-0.1.5.2, B"
  :precision binary64
  (* x (- 1 (* x 0.5))))