R \cdot \sqrt{\left(\left(\lambda_1 - \lambda_2\right) \cdot \cos \left(\frac{\phi_1 + \phi_2}{2}\right)\right) \cdot \left(\left(\lambda_1 - \lambda_2\right) \cdot \cos \left(\frac{\phi_1 + \phi_2}{2}\right)\right) + \left(\phi_1 - \phi_2\right) \cdot \left(\phi_1 - \phi_2\right)}R \cdot \mathsf{hypot}\left(\left(\lambda_1 - \lambda_2\right) \cdot \cos \left(\frac{\phi_1 + \phi_2}{2}\right), \phi_1 - \phi_2\right)double f(double R, double lambda1, double lambda2, double phi1, double phi2) {
double r73027 = R;
double r73028 = lambda1;
double r73029 = lambda2;
double r73030 = r73028 - r73029;
double r73031 = phi1;
double r73032 = phi2;
double r73033 = r73031 + r73032;
double r73034 = 2.0;
double r73035 = r73033 / r73034;
double r73036 = cos(r73035);
double r73037 = r73030 * r73036;
double r73038 = r73037 * r73037;
double r73039 = r73031 - r73032;
double r73040 = r73039 * r73039;
double r73041 = r73038 + r73040;
double r73042 = sqrt(r73041);
double r73043 = r73027 * r73042;
return r73043;
}
double f(double R, double lambda1, double lambda2, double phi1, double phi2) {
double r73044 = R;
double r73045 = lambda1;
double r73046 = lambda2;
double r73047 = r73045 - r73046;
double r73048 = phi1;
double r73049 = phi2;
double r73050 = r73048 + r73049;
double r73051 = 2.0;
double r73052 = r73050 / r73051;
double r73053 = cos(r73052);
double r73054 = r73047 * r73053;
double r73055 = r73048 - r73049;
double r73056 = hypot(r73054, r73055);
double r73057 = r73044 * r73056;
return r73057;
}



Bits error versus R



Bits error versus lambda1



Bits error versus lambda2



Bits error versus phi1



Bits error versus phi2
Results
Initial program 39.3
Simplified3.8
rmApplied *-commutative3.8
Final simplification3.8
herbie shell --seed 2020046 +o rules:numerics
(FPCore (R lambda1 lambda2 phi1 phi2)
:name "Equirectangular approximation to distance on a great circle"
:precision binary64
(* R (sqrt (+ (* (* (- lambda1 lambda2) (cos (/ (+ phi1 phi2) 2))) (* (- lambda1 lambda2) (cos (/ (+ phi1 phi2) 2)))) (* (- phi1 phi2) (- phi1 phi2))))))