Average Error: 0.3 → 0.3
Time: 1.3s
Precision: 64
\[\left(x \cdot 27\right) \cdot y\]
↓
\[\left(x \cdot 27\right) \cdot y\]
\left(x \cdot 27\right) \cdot y
↓
\left(x \cdot 27\right) \cdot y
double f(double x, double y) {
        double r193970 = x;
        double r193971 = 27.0;
        double r193972 = r193970 * r193971;
        double r193973 = y;
        double r193974 = r193972 * r193973;
        return r193974;
}
↓
double f(double x, double y) {
        double r193975 = x;
        double r193976 = 27.0;
        double r193977 = r193975 * r193976;
        double r193978 = y;
        double r193979 = r193977 * r193978;
        return r193979;
}

Error

Bits error versus x

Bits error versus y

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.3

    \[\left(x \cdot 27\right) \cdot y\]

  2. Final simplification0.3

    \[\leadsto \left(x \cdot 27\right) \cdot y\]

Reproduce

herbie shell --seed 2020046 +o rules:numerics
(FPCore (x y)
  :name "Diagrams.Solve.Polynomial:cubForm  from diagrams-solve-0.1, F"
  :precision binary64
  (* (* x 27) y))