\left(\left(x \cdot y + \frac{z \cdot t}{16}\right) - \frac{a \cdot b}{4}\right) + c\mathsf{fma}\left(z, \frac{t}{16}, \mathsf{fma}\left(y, x, \mathsf{fma}\left(-\frac{a}{4}, b, c\right)\right)\right)double f(double x, double y, double z, double t, double a, double b, double c) {
double r208567 = x;
double r208568 = y;
double r208569 = r208567 * r208568;
double r208570 = z;
double r208571 = t;
double r208572 = r208570 * r208571;
double r208573 = 16.0;
double r208574 = r208572 / r208573;
double r208575 = r208569 + r208574;
double r208576 = a;
double r208577 = b;
double r208578 = r208576 * r208577;
double r208579 = 4.0;
double r208580 = r208578 / r208579;
double r208581 = r208575 - r208580;
double r208582 = c;
double r208583 = r208581 + r208582;
return r208583;
}
double f(double x, double y, double z, double t, double a, double b, double c) {
double r208584 = z;
double r208585 = t;
double r208586 = 16.0;
double r208587 = r208585 / r208586;
double r208588 = y;
double r208589 = x;
double r208590 = a;
double r208591 = 4.0;
double r208592 = r208590 / r208591;
double r208593 = -r208592;
double r208594 = b;
double r208595 = c;
double r208596 = fma(r208593, r208594, r208595);
double r208597 = fma(r208588, r208589, r208596);
double r208598 = fma(r208584, r208587, r208597);
return r208598;
}



Bits error versus x



Bits error versus y



Bits error versus z



Bits error versus t



Bits error versus a



Bits error versus b



Bits error versus c
Initial program 0.1
Simplified0.0
Final simplification0.0
herbie shell --seed 2020046 +o rules:numerics
(FPCore (x y z t a b c)
:name "Diagrams.Solve.Polynomial:quartForm from diagrams-solve-0.1, C"
:precision binary64
(+ (- (+ (* x y) (/ (* z t) 16)) (/ (* a b) 4)) c))