Average Error: 0.0 → 0.0
Time: 2.8s
Precision: 64
\[x \cdot e^{y \cdot y}\]
↓
\[x \cdot e^{y \cdot y}\]
x \cdot e^{y \cdot y}
↓
x \cdot e^{y \cdot y}
double f(double x, double y) {
        double r789652 = x;
        double r789653 = y;
        double r789654 = r789653 * r789653;
        double r789655 = exp(r789654);
        double r789656 = r789652 * r789655;
        return r789656;
}
↓
double f(double x, double y) {
        double r789657 = x;
        double r789658 = y;
        double r789659 = r789658 * r789658;
        double r789660 = exp(r789659);
        double r789661 = r789657 * r789660;
        return r789661;
}

Error

Bits error versus x

Bits error versus y

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original0.0
Target0.0
Herbie0.0
\[x \cdot {\left(e^{y}\right)}^{y}\]

Derivation

  1. Initial program 0.0

    \[x \cdot e^{y \cdot y}\]

  2. Final simplification0.0

    \[\leadsto x \cdot e^{y \cdot y}\]

Reproduce

herbie shell --seed 2020046 +o rules:numerics
(FPCore (x y)
  :name "Data.Number.Erf:$dmerfcx from erf-2.0.0.0"
  :precision binary64

  :herbie-target
  (* x (pow (exp y) y))

  (* x (exp (* y y))))