Average Error: 0.0 → 0.0
Time: 4.3s
Precision: 64
\[x \cdot \left(y + 1\right)\]
\[x \cdot \left(y + 1\right)\]
x \cdot \left(y + 1\right)
x \cdot \left(y + 1\right)
double f(double x, double y) {
        double r1007510 = x;
        double r1007511 = y;
        double r1007512 = 1.0;
        double r1007513 = r1007511 + r1007512;
        double r1007514 = r1007510 * r1007513;
        return r1007514;
}

double f(double x, double y) {
        double r1007515 = x;
        double r1007516 = y;
        double r1007517 = 1.0;
        double r1007518 = r1007516 + r1007517;
        double r1007519 = r1007515 * r1007518;
        return r1007519;
}

Error

Bits error versus x

Bits error versus y

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original0.0
Target0.0
Herbie0.0
\[x + x \cdot y\]

Derivation

  1. Initial program 0.0

    \[x \cdot \left(y + 1\right)\]
  2. Final simplification0.0

    \[\leadsto x \cdot \left(y + 1\right)\]

Reproduce

herbie shell --seed 2020045 +o rules:numerics
(FPCore (x y)
  :name "Data.Colour.RGBSpace.HSL:hsl from colour-2.3.3, B"
  :precision binary64

  :herbie-target
  (+ x (* x y))

  (* x (+ y 1)))