R \cdot \sqrt{\left(\left(\lambda_1 - \lambda_2\right) \cdot \cos \left(\frac{\phi_1 + \phi_2}{2}\right)\right) \cdot \left(\left(\lambda_1 - \lambda_2\right) \cdot \cos \left(\frac{\phi_1 + \phi_2}{2}\right)\right) + \left(\phi_1 - \phi_2\right) \cdot \left(\phi_1 - \phi_2\right)}R \cdot \mathsf{hypot}\left(\left(\lambda_1 - \lambda_2\right) \cdot \cos \left(\frac{\phi_1 + \phi_2}{2}\right), \phi_1 - \phi_2\right)double f(double R, double lambda1, double lambda2, double phi1, double phi2) {
double r98998 = R;
double r98999 = lambda1;
double r99000 = lambda2;
double r99001 = r98999 - r99000;
double r99002 = phi1;
double r99003 = phi2;
double r99004 = r99002 + r99003;
double r99005 = 2.0;
double r99006 = r99004 / r99005;
double r99007 = cos(r99006);
double r99008 = r99001 * r99007;
double r99009 = r99008 * r99008;
double r99010 = r99002 - r99003;
double r99011 = r99010 * r99010;
double r99012 = r99009 + r99011;
double r99013 = sqrt(r99012);
double r99014 = r98998 * r99013;
return r99014;
}
double f(double R, double lambda1, double lambda2, double phi1, double phi2) {
double r99015 = R;
double r99016 = lambda1;
double r99017 = lambda2;
double r99018 = r99016 - r99017;
double r99019 = phi1;
double r99020 = phi2;
double r99021 = r99019 + r99020;
double r99022 = 2.0;
double r99023 = r99021 / r99022;
double r99024 = cos(r99023);
double r99025 = r99018 * r99024;
double r99026 = r99019 - r99020;
double r99027 = hypot(r99025, r99026);
double r99028 = r99015 * r99027;
return r99028;
}



Bits error versus R



Bits error versus lambda1



Bits error versus lambda2



Bits error versus phi1



Bits error versus phi2
Results
Initial program 38.5
Simplified3.7
rmApplied *-commutative3.7
Final simplification3.7
herbie shell --seed 2020045 +o rules:numerics
(FPCore (R lambda1 lambda2 phi1 phi2)
:name "Equirectangular approximation to distance on a great circle"
:precision binary64
(* R (sqrt (+ (* (* (- lambda1 lambda2) (cos (/ (+ phi1 phi2) 2))) (* (- lambda1 lambda2) (cos (/ (+ phi1 phi2) 2)))) (* (- phi1 phi2) (- phi1 phi2))))))