Average Error: 0.7 → 0.8
Time: 10.5s
Precision: 64
\[\frac{e^{a}}{e^{a} + e^{b}}\]
\[\frac{1}{\frac{e^{a} + e^{b}}{e^{a}}}\]
\frac{e^{a}}{e^{a} + e^{b}}
\frac{1}{\frac{e^{a} + e^{b}}{e^{a}}}
double f(double a, double b) {
        double r110716 = a;
        double r110717 = exp(r110716);
        double r110718 = b;
        double r110719 = exp(r110718);
        double r110720 = r110717 + r110719;
        double r110721 = r110717 / r110720;
        return r110721;
}

double f(double a, double b) {
        double r110722 = 1.0;
        double r110723 = a;
        double r110724 = exp(r110723);
        double r110725 = b;
        double r110726 = exp(r110725);
        double r110727 = r110724 + r110726;
        double r110728 = r110727 / r110724;
        double r110729 = r110722 / r110728;
        return r110729;
}

Error

Bits error versus a

Bits error versus b

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original0.7
Target0.0
Herbie0.8
\[\frac{1}{1 + e^{b - a}}\]

Derivation

  1. Initial program 0.7

    \[\frac{e^{a}}{e^{a} + e^{b}}\]
  2. Using strategy rm
  3. Applied clear-num0.8

    \[\leadsto \color{blue}{\frac{1}{\frac{e^{a} + e^{b}}{e^{a}}}}\]
  4. Final simplification0.8

    \[\leadsto \frac{1}{\frac{e^{a} + e^{b}}{e^{a}}}\]

Reproduce

herbie shell --seed 2020045 
(FPCore (a b)
  :name "Quotient of sum of exps"
  :precision binary64

  :herbie-target
  (/ 1 (+ 1 (exp (- b a))))

  (/ (exp a) (+ (exp a) (exp b))))