Average Error: 0.0 → 0.0
Time: 6.0s
Precision: 64
\[x \cdot \left(y + 1\right)\]
\[x \cdot \left(y + 1\right)\]
x \cdot \left(y + 1\right)
x \cdot \left(y + 1\right)
double f(double x, double y) {
        double r788262 = x;
        double r788263 = y;
        double r788264 = 1.0;
        double r788265 = r788263 + r788264;
        double r788266 = r788262 * r788265;
        return r788266;
}

double f(double x, double y) {
        double r788267 = x;
        double r788268 = y;
        double r788269 = 1.0;
        double r788270 = r788268 + r788269;
        double r788271 = r788267 * r788270;
        return r788271;
}

Error

Bits error versus x

Bits error versus y

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original0.0
Target0.0
Herbie0.0
\[x + x \cdot y\]

Derivation

  1. Initial program 0.0

    \[x \cdot \left(y + 1\right)\]
  2. Final simplification0.0

    \[\leadsto x \cdot \left(y + 1\right)\]

Reproduce

herbie shell --seed 2020045 
(FPCore (x y)
  :name "Data.Colour.RGBSpace.HSL:hsl from colour-2.3.3, B"
  :precision binary64

  :herbie-target
  (+ x (* x y))

  (* x (+ y 1)))