Average Error: 0.0 → 0.0
Time: 4.3s
Precision: 64
\[x \cdot \left(1 - x \cdot 0.5\right)\]
↓
\[x \cdot \left(1 - x \cdot 0.5\right)\]
x \cdot \left(1 - x \cdot 0.5\right)
↓
x \cdot \left(1 - x \cdot 0.5\right)
double f(double x) {
        double r174573 = x;
        double r174574 = 1.0;
        double r174575 = 0.5;
        double r174576 = r174573 * r174575;
        double r174577 = r174574 - r174576;
        double r174578 = r174573 * r174577;
        return r174578;
}
↓
double f(double x) {
        double r174579 = x;
        double r174580 = 1.0;
        double r174581 = 0.5;
        double r174582 = r174579 * r174581;
        double r174583 = r174580 - r174582;
        double r174584 = r174579 * r174583;
        return r174584;
}

Error

Bits error versus x

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.0

    \[x \cdot \left(1 - x \cdot 0.5\right)\]

  2. Final simplification0.0

    \[\leadsto x \cdot \left(1 - x \cdot 0.5\right)\]

Reproduce

herbie shell --seed 2020043 +o rules:numerics
(FPCore (x)
  :name "Numeric.SpecFunctions:log1p from math-functions-0.1.5.2, B"
  :precision binary64
  (* x (- 1 (* x 0.5))))