R \cdot \sqrt{\left(\left(\lambda_1 - \lambda_2\right) \cdot \cos \left(\frac{\phi_1 + \phi_2}{2}\right)\right) \cdot \left(\left(\lambda_1 - \lambda_2\right) \cdot \cos \left(\frac{\phi_1 + \phi_2}{2}\right)\right) + \left(\phi_1 - \phi_2\right) \cdot \left(\phi_1 - \phi_2\right)}R \cdot \mathsf{hypot}\left(\left(\lambda_1 - \lambda_2\right) \cdot \cos \left(\frac{\phi_1 + \phi_2}{2}\right), \phi_1 - \phi_2\right)double f(double R, double lambda1, double lambda2, double phi1, double phi2) {
double r98061 = R;
double r98062 = lambda1;
double r98063 = lambda2;
double r98064 = r98062 - r98063;
double r98065 = phi1;
double r98066 = phi2;
double r98067 = r98065 + r98066;
double r98068 = 2.0;
double r98069 = r98067 / r98068;
double r98070 = cos(r98069);
double r98071 = r98064 * r98070;
double r98072 = r98071 * r98071;
double r98073 = r98065 - r98066;
double r98074 = r98073 * r98073;
double r98075 = r98072 + r98074;
double r98076 = sqrt(r98075);
double r98077 = r98061 * r98076;
return r98077;
}
double f(double R, double lambda1, double lambda2, double phi1, double phi2) {
double r98078 = R;
double r98079 = lambda1;
double r98080 = lambda2;
double r98081 = r98079 - r98080;
double r98082 = phi1;
double r98083 = phi2;
double r98084 = r98082 + r98083;
double r98085 = 2.0;
double r98086 = r98084 / r98085;
double r98087 = cos(r98086);
double r98088 = r98081 * r98087;
double r98089 = r98082 - r98083;
double r98090 = hypot(r98088, r98089);
double r98091 = r98078 * r98090;
return r98091;
}



Bits error versus R



Bits error versus lambda1



Bits error versus lambda2



Bits error versus phi1



Bits error versus phi2
Results
Initial program 38.9
Simplified3.6
rmApplied *-commutative3.6
Final simplification3.6
herbie shell --seed 2020036 +o rules:numerics
(FPCore (R lambda1 lambda2 phi1 phi2)
:name "Equirectangular approximation to distance on a great circle"
:precision binary64
(* R (sqrt (+ (* (* (- lambda1 lambda2) (cos (/ (+ phi1 phi2) 2))) (* (- lambda1 lambda2) (cos (/ (+ phi1 phi2) 2)))) (* (- phi1 phi2) (- phi1 phi2))))))